Please use this identifier to cite or link to this item:
http://hdl.handle.net/11452/24509
Title: | The number of solutions of pell equations x2 -ky2 = N and x2+xy- Ky2 = N over Fp |
Authors: | Uludağ Üniversitesi/Fen-Edebiyat Fakültesi/Matematik Anabilim Dalı. Tekcan, Ahmet AAH-8518-2021 55883777900 |
Keywords: | Mathematics Pell equation Solutions of the Pell equation Finite field |
Issue Date: | Oct-2011 |
Publisher: | Charles Babbage Res CTR |
Citation: | Tekcan, A. (2011). "The number of solutions of pell equations x2 -ky2 = N and x2+xy- Ky2 = N over Fp". Ars Combinatoria, 102, 225-236. |
Abstract: | Let p be a prime number such that p equivalent to 1, 3(mod 4), let F-p, be a finite field, let N is an element of F-p* = F-p - {0} be a fixed. Let P-p(k) (N) : x(2) - ky(2) = N and (P) over tilde (k)(p)(N) : x(2) + xy - ky(2) = N be two Pell equations over F-p, where k = p-1/4 or k = p-3/4, respectively. Let P-p(k)(N)(F-p) and (P) over tilde (k)(p)(N)(F-p) denote the set of integer solutions of the Pell equations P-p(k)(N) and (P) over tilde (k)(p)(N), respectively. In the first section we give some preliminaries from general Pell equation x(2) - ky(2) = +/- N. In the second section, we determine the number of integer solutions of P-p(k)(N). We proved that P-p(k)(N)(F-p) = p+ 1 if p equivalent to 1(mod 4) or p equivalent to 7(mod 12) and P-p(k)(N)(F-p) = p - 1 if p equivalent to 11(mod 12). In the third section we consider the Pell equation (P) over tilde (k)(p)(N). We proved that (P) over tilde (k)(p)(N)(F-p) = 2p if p equivalent to 1(mod 4) and N is an element of Q(p); (P) over tilde (k)(p)(N)(F-p) = 0 if p equivalent to 1(mod 4) and N is not an element of Q(p) ; (P) over tilde (k)(p)(N)(F-p) = p + 1 if p equivalent to 3(mod 4). |
URI: | http://hdl.handle.net/11452/24509 |
ISSN: | 0381-7032 |
Appears in Collections: | Scopus Web of Science |
Files in This Item:
There are no files associated with this item.
Items in DSpace are protected by copyright, with all rights reserved, unless otherwise indicated.